[Harp-L] Impedance questions and some (probably) crazy thoughts on volume controls in crystal mics
- To: harp-l@xxxxxxxxxx
- Subject: [Harp-L] Impedance questions and some (probably) crazy thoughts on volume controls in crystal mics
- From: Tom Skailes <tom.skailes@xxxxxxxxxxxx>
- Date: Sat, 19 Feb 2011 14:10:37 +0000
- User-agent: Mozilla/5.0 (Windows; U; Windows NT 6.1; en-US; rv:1.9.2.13) Gecko/20101207 Thunderbird/3.1.7
Hi Guys
This may cover some old ground, so apologies if that's the case.
I'm just getting round to building a Jayphat impedance matching box so I
can run a delay/echo pedal with my MC-151 blues blaster crystal mic.
Been thinking about achieving a good high impedance to the crystal
element and had a number of thoughts/questions that it would be great to
get some feedback/advice on - I haven't looked at circuit theory for
over 30 years so you'll have to forgive my ignorance ;) :
1 - my blaster has a 2 Meg vol control pot in the Rod Piazza 'Hot Rod'
circuit configuration (I think) with the capacitor. I have a 5.6Meg
resistor in the input of my Bassman RI. Because the pot and the resistor
are in parallel, my understanding is that when the pot is full on, the
effective impedance to the crystal is 1474k. The first question is, when
the vol pot is turned to say half, the circuit layout suggests that this
presents part of the pot resistor in series, with the remainder in
parallel with the amp's resistor, so at the exact halfway point I
(probably wrongly) calculate an impedance to the crystal of 1Meg + 848k
- is this correct, or does it remain constant, regardless of the vol pot
setting?
2 - On the JT30 site I found an article that mentioned putting a
resistor in parallel across the output from the vol pot as a means to
make a linear taper pot more 'audio' in its operation. The author of the
article stated that the crystal would see the full impedance of the vol
pot, whilst the amp would see the impedance of the resistor after the
pot. To me this doesn't sound correct - but I could well be wrong - my
thoughts are that a 5Meg pot with a 1Meg resistor following in parallel
across the outputs, coupled with the typical 1Meg resistor in the input
of a guitar amp would at full pot volume result in an impedance to the
crystal of 454k, whilst at the halfway volume point, provided my maths
is correct, 2.5Meg + 416k (result of 2.5M/1M/1M in parallel)? Which is
right?
3 - The volume pot can dull the tone of the crystal and some people
suggest removing the vol pot from the mic circuit. With my Bassman that
would give me the full 5.6Meg impedance to the crystal, or on a typical
guitar amp input 1Meg. This leads to my first probably crazy question -
to avoid the problem of parallel resistors dropping the impedance to the
crystal, would it be possible/sensible to remove the amp's input
impedance resistor from the circuit, based on the (probably erroneous)
assumption that the vol pot in the mic effectively replaces it. I'm
thinking this might be OK when the mic is connected to the amp, but
might cause excessive squealing or hum when the mic jack is pulled from
the amp socket. What's the story on this?
4 - As per 3, what would the effect be of dropping the 5.6Meg input
resistor out of the Jayphat circuit - would anything get fried if the
Jayphat was accidentally turned on without a mic jack connected? My
understanding is that the J-FET in the Jayphat has essentially infinite
impedance. I'm guessing that this might only be beneficial for crystal
elements, if at all. This is related to a second article on the JT30
site which suggested putting an op amp inside the mic between the
element and the pot, so that the crystal saw a massive impedance, but
the amp saw much less - this sounds a bit like trying to cram the
Jayphat circuit plus two 9v batteries between the crystal and the vol
pot, with the vol pot as part of the Jayphat circuit - has anyone tried
this?
5 - Final crazy question/thought: Is it possible to wire the vol pot in
the mic so it's a variable resistor in series with the crystal element?
I'm guessing that at full 'off' on the pot, sound would still come
through, the level of which would depend of the ratio between the pot
and the amp's input resistor. Would this work? In this configuration I'm
guessing that the minimum impedance presented to the crystal would be
the value of the amp's input resistor, and the maximum would be the sum
of the pot plus resistor???
Anyway, as I said, there is probably some/much wrong/muddled thinking
amongst the above, and I'll probably just end up building the Jayphat as
per the schematic on the Harp-L site, but it all got me thinking.
Regards
Tom
This archive was generated by a fusion of
Pipermail 0.09 (Mailman edition) and
MHonArc 2.6.8.